A) Seismically derived | Â |
 Mean sedimentation rate | 0.03 m/yr |
 Total basin plain area | 5.05 × 106 m2 |
 Mean sediment accumulation within 15 yrs | 15 yr × 0.03 m/yr  = 0.435 m |
 Sediment volume | 0.435 m × 5.05 × 106 m2  = 2.2 × Mio m3 |
 Sediment dry mass in 15 years (incl. event deposits) | 1855 kg/m3 × 2.2 Mio m3  = 4.08 Mio t |
B) Instrumentally derived (suspended load) | Â |
 Avg. river input: within 15 years: 2005 flood input: (Bezzola & Hegg, 2007) | 0.302 Mio. t yr−1 15 yr × 0.302 Mio. t yr−1  = 4.53 Mio. t 0.42 + 0.59 Mio. t  = 1.01 Mio. t |
 Total river input: | 4.53 + 1.01 Mio. t  = 5.54 Mio. t |